Q.

Let a tangent to the curve y2 = 24x meet the curve xy = 2 at the points A and B. Then the mid points of such line segments AB lie on a parabola with the

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a

length of latus rectum 2

b

length of latus rectum 3/2

c

directrix 4x = 3

d

directrix 4x = -3

answer is C.

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Detailed Solution

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Let P(x1, y1) be midpoint of AB of curve xy = 2 then equation of AB is S1 = S11
12xy1+x1y=12x1y1
xy1 + x1y - x1y1 = 0 is tangent of y2 = 24x
am2 = In
Locus is 6(x12) = y1(-x1y1)
Locus is y2 = -6x
Directrix is 4x = 3

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