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Q.

Let a vertical tower AB   of height 2h  stands on a horizontal ground. Let from a point P  on the ground a man can see upto height h   of the tower with an angle of elevation 2α . When from  P  he moves a distance  d in the direction of AP,  he can see the top B of the tower with an angle of elevation α  . If d=7h  , then  tanα is equal to

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a

73

b

52

c

72

d

76

answer is C.

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Detailed Solution

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 Question Image
tan2α=hx and  tanα=2hx+7h
tanα=21tan2α2tanα+7 1-tan2α+27 tanα=4 tan2α-27 tanα+3=0
On solving we get           tanα=72
 

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