Q.

Let a≠0 and P(x) be a polynomial of degree greater than 2. If P(x) leaves remainder a and –a when divided respectively by x + a and x – a then  the   remainder when P(x) is divided by x2 a2 is

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a

–x

b

–2x

c

2x

d

x

answer is D.

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Detailed Solution

IfP(x)dividedbyx+aandxaThenRemaindersareP(a)=a  and  P(a)=aLettheRemainderwhenP(x)isdividedbyx2a2beAx+BP(x)=Q(x)(x2a2)+(Ax+B)Putx=aP(a)=Q(a)(a2a2)+Aa+BAa+B=a(1)Putx=aP(a)=Q(a)(a2a2)Aa+BAa+B=a(2)(1)+(2)2B=0B=0from(1)  Aa=aA=1Remainder=Ax+B=x

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