Q.

Let A1,A2,A3 be the three series in AP, with same common difference ‘d’ and their first terms  A,A+1,A+2are  if a, b, c are 7th, 9th, 17th terms A1,A2,A3 of  such that

|a712b171c171|+70=0

If a=29 then sum of first 20 terms of an AP where first term c –a  = b with common difference d12  is 

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answer is 495.

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Detailed Solution

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|A+6d712(A+1+8d)171A+2+16d171|+70=0A=7   and  d=6cab=20Sn=n2[2a+(n1)d]=10[40+19(12)]=5[80+19]=5(79)=495

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