Let a1,a2 ,a3 ,.....,a4001 are in A.P. such that 1a1a2+1a2a3+….+1a4000a4001=10 and a2 + a4000 = 50 then a1−a4001 is equal to

4000a1a4001=10⇒a1a4001=400 also a1+a4001=50⇒a1−a40012=2500−1600⇒a1−a4001=30

Let a1,a2 ,a3 ,.....,a4001 are in A.P. such that 1a1a2+1a2a3+….+1a4000a4001=10 and a2 + a4000 = 50 then a1−a4001 is equal to

4000a1a4001=10⇒a1a4001=400 also a1+a4001=50⇒a1−a40012=2500−1600⇒a1−a4001=30

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Let a₁,a₂ ,a₃ ,.....,a₄₀₀₁ are in A.P. such that $\frac{1}{a_{1} a_{2}} + \frac{1}{a_{2} a_{3}} + \dots . + \frac{1}{a_{4000} a_{4001}} = 10$ and a₂ + a₄₀₀₀ = 50 then $|a_{1} - a_{4001}|$ is equal to

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$\begin{array}{l} \frac{4000}{a_{1} a_{4001}} = 10 \Rightarrow a_{1} a_{4001} = 400 also \\ a_{1} + a_{4001} = 50 \Rightarrow {|a_{1} - a_{4001}|}^{2} = 2500 - 1600 \\ \Rightarrow |a_{1} - a_{4001}| = 30 \end{array}$

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Let a1,a2 ,a3 ,.....,a4001 are in A.P. such that 1a1a2+1a2a3+….+1a4000a4001=10 and a2 + a4000 = 50 then a1−a4001 is equal to

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Let a₁,a₂ ,a₃ ,.....,a₄₀₀₁ are in A.P. such that $\frac{1}{a_{1} a_{2}} + \frac{1}{a_{2} a_{3}} + \dots . + \frac{1}{a_{4000} a_{4001}} = 10$ and a₂ + a₄₀₀₀ = 50 then $|a_{1} - a_{4001}|$ is equal to