Let $A=\left[\begin{array}{c}32\\ 11\end{array}\right]$ satisfies $A^2+aA+bI=0$ , then $a,b$ are respectively equal to

$A^2+aA+bI=0$

${\left[\begin{array}{c}32\\ 11\end{array}\right]}^2+a\left[\begin{array}{c}32\\ 11\end{array}\right]+b\left[\begin{array}{c}10\\ 01\end{array}\right]=0$

$\left[\begin{array}{c}118\\ 43\end{array}\right]+\left[\begin{array}{c}3a2a\\ aa\end{array}\right]+\left[\begin{array}{c}b0\\ 0b\end{array}\right]=0$

$\left[\begin{array}{c}11+3a+b8+2a+0\\ 4+a+03+a+b\end{array}\right]=0$

$a=-4$ , $b=1$