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Q.

Let an  be the nth  term of G.P. If n=1100a2n=α  and n=1100a2n1=β , then the common ratio of the G.P is

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a

αβ

b

βα

c

αβ

d

βα

answer is C.

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Detailed Solution

a2+a4+a6++a200=α

ar+ar3+ar5++ar199=α

ar[1+r2+r4++r198]=α(1)

a1+a3+a5++a199=β

a+ar2+ar4++ar198=β

a[1+r2+r4++r198]=β(2)

(1)(2)r=αβ

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Let an  be the nth  term of G.P. If ∑n=1100a2n=α  and ∑n=1100a2n−1=β , then the common ratio of the G.P is