Q.

Let  an=3n+n21 and bn=2(n2n+n2+n),n1 , then the value of   a1b1+a2b2++a49b49=c+d2 for some integer  c and  d then which  is/are  INCORRECT ?

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a

d2c=14

b

c+2d=3

c

dc=9

d

c+d=1

answer is A, B, D.

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Detailed Solution

anbn=12[(n+1n)(nn1)]=452

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