Q.

Let an be the nth term of a G.P. of positive terms. If n=1100a2n+1=200   and n=1100a2nn=1100a2n=100, then n=1200an is  equal to

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a

150

b

175

c

225

d

300

answer is D.

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Detailed Solution

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a3+a5+.......+a201=a3[(r2)1001](r21)=200  and  a2+a4+.......+a200=a2[(r2)1001](r21)=100
Division gives a3a2=r=2 . Hence  a2=100(3)41001a1=15041001
 

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Let an be the nth term of a G.P. of positive terms. If ∑n=1100a2n+1=200   and ∑n=1100a2n∑n=1100a2n=100, then ∑n=1200an is  equal to