Let α, β and γ be real numbers. Consider the following system of linear equations
x + 2y + z = 7
x + αz = 11
2x – 3y + βz = γ
Match each entry in List-I to the correct entries in List-II.

	List-I		List-II
P)	If $\mathrm{\beta }=\frac{1}{2}(7\mathrm{\alpha }-3)$ and $\mathrm{\gamma }=28$ then the system has	1)	a unique solution
Q)	If $\mathrm{\beta }=\frac{1}{2}(7\mathrm{\alpha }-3)$ and $\mathrm{\gamma }\ne 28$, then the system has	2)	no solution
R)	If $\mathrm{\beta }\ne \frac{1}{2}(7\mathrm{\alpha }-3)$, where $\mathrm{\alpha } = 1$ and $\mathrm{\gamma }\ne 28$, then the system has	3)	infinitely many solutions
S)	If $\mathrm{\beta }\ne \frac{1}{2}(7\mathrm{\alpha }-3)$ where $\mathrm{\alpha } = 1$ and $\mathrm{\gamma }=28$, then the system has	4)	x = 11, y = –2 and z = 0 as a solution
		5)	x = –15, y = 4 and z = 0 as a solution

	P	Q	R	S
1)	3	2	1	4
2)	3	2	5	4
3)	2	1	4	5
4)	2	1	1	3