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Q.

Let α, ß, γ and δ be the coefficients of x7, x5, x3 and x respectively in the expansion of x+x315+xx315,x>1.If u and v satisfy the equations
αu+βv=18γu+δv=20
then u + v equals :

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a

8

b

3

c

4

d

5

answer is A.

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Detailed Solution

 x+x315+xx315 =2 5C0x5+5C2x3x31+5C4xx312 =25x7+10x6+x510x410x3+5x α=10,β=2,γ=20,δ=10 Now, 10u+2v=18 20u+10v=20 u=1,v=4 u+v=5

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