Q.

Let α  and β   be two roots of the equation x2+2x+2=0,  then α15+β15  is equal to

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a

-256

b

 -512

c

256

d

512

answer is C.

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Detailed Solution

(x+1)2+1=0      (x+1)2(i)2=0   (x+1+i)(x+1i)=0 x=(1+i)α(let),(1i)β(let)   So,  α15+β15=(α2)7α+(β2)7β =128(i+1+i+1)   =256

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