Q.

Let AP (a; d) denote the set of all the terms of an infinite arithmetic progression with first term a and common difference d > 0. If AP(1;3)AP(2;5)AP(3;7)=AP(a;d) then a+ d equals

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Detailed Solution

Let 1+3m=2+5n=3+7r

The first common term is given by setting r=7

 a=52

and d = least common multiple of 3, 5, 7 = 105

Hence, a+d=105+52=157

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