Let B=13a123aa4,a>2be the adjoint of a matrix A and |A|=2,Then a-2aaBa−2aa is equal to λ then λ=

|B|=|adjA|=|A|2⇒a2−6a+8=0⇒a=4(since a>2)Now (4−8 4) 134123444 4−84=−16

Let B=13a123aa4,a>2be the adjoint of a matrix A and |A|=2,Then a-2aaBa−2aa is equal to λ then λ=

|B|=|adjA|=|A|2⇒a2−6a+8=0⇒a=4(since a>2)Now (4−8 4) 134123444 4−84=−16

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Let $B = [\begin{matrix} 1 & 3 & a \\ 1 & 2 & 3 \\ a & a & 4 \end{matrix}], a > 2$ be the adjoint of a matrix A and $| A | = 2,$ Then $[\begin{matrix} a & - 2 a & a \end{matrix}] B [\begin{matrix} a \\ - 2 a \\ a \end{matrix}]$ is equal to $[\begin{matrix} λ \end{matrix}]$ then $λ =$

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$| B | = | adjA | = {| A |}^{2} \Rightarrow a^{2} - 6 a + 8 = 0 \Rightarrow a = 4$ (since a>2)
Now $(4 - 8 4) (\begin{matrix} 1 & 3 & 4 \\ 1 & 2 & 3 \\ 4 & 4 & 4 \end{matrix}) (\begin{matrix} 4 \\ - 8 \\ 4 \end{matrix}) = (- 16)$

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Let B=13a123aa4,a>2be the adjoint of a matrix A and |A|=2,Then a-2aaBa−2aa is equal to λ then λ=

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Let $B = [\begin{matrix} 1 & 3 & a \\ 1 & 2 & 3 \\ a & a & 4 \end{matrix}], a > 2$ be the adjoint of a matrix A and $| A | = 2,$ Then $[\begin{matrix} a & - 2 a & a \end{matrix}] B [\begin{matrix} a \\ - 2 a \\ a \end{matrix}]$ is equal to $[\begin{matrix} λ \end{matrix}]$ then $λ =$