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Q.

Let α,β,γ be the roots of x3+x+10=0. Write α1=α+βγ2,β1=β+γα2,γ1=γ+αβ2. Then the value of α13+β13+γ13-110α12+β12+γ12 is

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a

15

b

310

c

110

d

12

answer is C.

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Detailed Solution

 α,β,γ be the roots of x3+x+10=0. 
α+β+γ=0,
 α1=α+βγ2=-γγ2=-1γ,β1=β+γα2=-αα2=-1α,γ1=γ+αβ2=-ββ2=-1β .
 The equation whose roots are α1,β1,γ1 is f-1x=0-1x3-1x+10=0

10x3-x2-1=0

α1+β1+γ1=110,α1β1+β1γ1+γ1α1=0,α1β1γ1=110 

α12+β12+γ12=α1+β1+γ12-2α1β1+β1γ1+γ1α1=1100 α12+β12+γ12=1100

α1+β1+γ13=α13+β13+γ13+3α1+β1+γ1α1β1+β1γ1+γ1α1-,α1β1γ1

11000=α13+β13+γ13+30-110α13+β13+γ13=11000+310 

α13+β13+γ13-110α12+β12+γ12=11000+310-1101100=310

 

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