Q.

Let C1 and C2 be the centres of the circles x2+y22x2y2=0 and x2+y26x6y+14=0 respectively. If P and Q are the points of intersection of these circles then, the area (in sq units) of the quadrilateral PC1 QC2 is

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a

8

b

6

c

9

d

4

answer is D.

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Detailed Solution

2g1g2+2f1f2=2(1)(3)+2(1)(3)=12c1+c2=142=12

Since, 2g1g2+2f1f2=c1+c2

Hence, circles intersect orthogonally

 Area of the quadrilateral PC1QC1

=2×12r1r2=(2)(2)=4sq. units 

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