Q.

Let C1,C2,C3,...... be the circles with radius r1 such that equation of circle C1:x2+y2=t12. Circle C1 intersects positive x-axis and y-axis at A1 and B1 respectively. There exist a point Pi, perpendicular from Pi on OAi and OBi are points Di and Ei respectively such that  ODi:OEi=3:4 and there exist a point Qi on circle Ci+1, if  AiQi=PiQi and AiQiPi=π2. If Si be the area of triangle AiQiPi and r1>r2>r3>.....>rn, where r1=1, then limn(i=1nSi) is less than or equal to :

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a

18

b

58

c

34

d

14

answer is A, B, D.

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Detailed Solution

AiPi=25ri  andri+1=ri5 
And  Si=r125Si+1=ri+125=r1225
 Si+1Si=15
 limn(S1+S2+S3+.....+Sn)=limn(15115)=14

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