Let E and F be two independent events . The probability that exactly one of them occurs is 1125 and probability of none of them occurring is 225 . If PT denotes the probability of occurrences of event T. Then

Solve the equations PE∪F−PE∩F=1125PE¯∩F¯=225

Let E and F be two independent events . The probability that exactly one of them occurs is 1125 and probability of none of them occurring is 225 . If PT denotes the probability of occurrences of event T. Then

Solve the equations PE∪F−PE∩F=1125PE¯∩F¯=225

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Let E and F be two independent events . The probability that exactly one of them occurs is $\frac{11}{25}$ and probability of none of them occurring is $\frac{2}{25}$ . If $P (T)$ denotes the probability of occurrences of event T. Then

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$P (E) = \frac{1}{5}, P (F) = \frac{2}{5}$

$P (E) = \frac{4}{5}, P (F) = \frac{3}{5}$

$P (E) = \frac{2}{5}, P (F) = \frac{1}{5}$

$P (E) = \frac{3}{5}, P (F) = \frac{4}{5}$

answer is A, D.

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Solve the equations $P (E \cup F) - P (E \cap F) = \frac{11}{25}$

$P (\bar{E} \cap \bar{F}) = \frac{2}{25}$

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Let E and F be two independent events . The probability that exactly one of them occurs is 1125 and probability of none of them occurring is 225 . If PT denotes the probability of occurrences of event T. Then

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Let E and F be two independent events . The probability that exactly one of them occurs is $\frac{11}{25}$ and probability of none of them occurring is $\frac{2}{25}$ . If $P (T)$ denotes the probability of occurrences of event T. Then