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Q.

Let f and g be two differentiable functions on R such that f ' (x)> 0 and g '(x)< 0 , for all x R. Then for all x

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a

f (g(x))>f (g (x- 1))

b

f(g(x))>f(g(x+1))

c

g(f(x))>gfx-1

d

g(f(x))>gfx+1

answer is B.

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Detailed Solution

f'(x)>0, and g'(x)<0 f is an increasing function and g is decreasing function x>x-1                                      g(x)<g(x-1)                              f(g(x))<f(g(x-1))                  f(g(x))>f(g(x+1)) and   x<x+1g(x)>g(x+1)  f(g(x))>f(g(x+1)) Option B is correct 

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