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Q.

Let f and g be two functions defined by f(x)={x+1,x<0|x1|,x0 and g(x)={x+1,x<01,x0 Then (gof)(x) is 

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a

continuous everywhere

b

continuous everywhere but not differentiable at x = 1

c

continuous everywhere but not differentiable exactly at one point

d

not continuous at x=1

answer is D.

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Detailed Solution

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g(f(x))=f(x)+1,f(x)<0 g(f(x))=x+1+1,x+1<0,x<1 =1  ,x1

 gof x=x+2x<11x1
Continuous at x=1 differentiable at x=1 not differentiable at x=1

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