Q.

Let  f  be a differentiable function such that  x2fxx=40xtftdt,iff1=23 Then 18 f(3)  is equal to

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a

180

b

160

c

210

d

150 

answer is C.

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Detailed Solution

 x2f(x)x=40xtf(t)dt
Diff w.r.tx
 x2f1(x)+f(x).2x=1=4xf(x) x2dydx+2xy1=4xydydx+(2x)y=1x2

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