Let f be a real valued function such that  $f\left(x\right)+2f\left(\frac{2002}{x}\right)=3x.$ Then  $f\left(x\right)=$

$giventhatf\left(x\right)+2f\left(\frac{2002}{x}\right)=3x\left(1\right)$

Replace  $\text{'}x\text{'}by\frac{2002}{x},weget$

$3f\left(x\right)=6\left(\frac{2002}{x}\right)-3x$

$\Rightarrow f\left(x\right)=2\left(\frac{2002}{x}\right)-\frac{x}{1}$

$=\frac{4004}{x}-x$