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Let f be two real valued functions with domain $A = {- 2, 0, 2}$ . If $f = {(- 2, 4), (0, 6), (2, 8)}$ and $g = \{(- 2, - 1), (0, 3), (2, 5)\}$ , then $(\frac{(2 f)}{(3 g)} + \frac{(3 g)}{(2 f)}) (0) =$

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$\frac{13}{12}$

$\frac{5}{12}$

$\frac{25}{12}$

$\frac{1}{12}$

answer is B.

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Detailed Solution

$A = {- 2, 0, 2} f = {(- 2, 4), (0, 6), (2, 8)}, g = {(- 2, - 1), (0, 3), (2, 5)}$

$(\frac{(2 f)}{(3 g)} + \frac{(3 g)}{(2 f)}) (0)$

$f (0) = 6, g (0) = 3$

$\frac{2 \times 6}{3 \times 3} + \frac{3 \times 3}{2 \times 6} = \frac{4}{3} + \frac{3}{4} = \frac{25}{12}$

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