Let f:R→R and g:R→R be respectively given by f(x)=|x|+1 and g(x)=x2+1. Define h:R→R by h(x)={max{f(x),g(x)} if x≤0min{f(x),g(x)} if x>0 Then number of points at which h(x) is not differentiable is

h(x)={x2+1,x∈(−∞,−1]−x+1,x∈(−1,0]x2+1,x∈(0,1]x+1,x∈(1,∞)It is not differentiable at x=−1,0,1

Let f:R→R and g:R→R be respectively given by f(x)=|x|+1 and g(x)=x2+1. Define h:R→R by h(x)={max{f(x),g(x)} if x≤0min{f(x),g(x)} if x>0 Then number of points at which h(x) is not differentiable is

h(x)={x2+1,x∈(−∞,−1]−x+1,x∈(−1,0]x2+1,x∈(0,1]x+1,x∈(1,∞)It is not differentiable at x=−1,0,1

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Let $f : R \to R a n d g : R \to R$ be respectively given by $f (x) = | x | + 1 a n d g (x) = x^{2} + 1.$ Define $h : R \to R$ by $h (x) = {\begin{cases} \max {f (x), g (x)} i f x \leq 0 \\ \min {f (x), g (x)} i f x > 0 \end{cases}$ Then number of points at which $h (x)$ is not differentiable is

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$h (x) = {\begin{cases} x^{2} + 1, x \in (- \infty, - 1] \\ - x + 1, x \in (- 1, 0] \\ x^{2} + 1, x \in (0, 1] \\ x + 1, x \in (1, \infty) \end{cases}$ It is not differentiable at $x = - 1, 0, 1$

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Let f:R→R and g:R→R be respectively given by f(x)=|x|+1 and g(x)=x2+1. Define h:R→R by h(x)={max{f(x),g(x)} if x≤0min{f(x),g(x)} if x>0 Then number of points at which h(x) is not differentiable is

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Let $f : R \to R a n d g : R \to R$ be respectively given by $f (x) = | x | + 1 a n d g (x) = x^{2} + 1.$ Define $h : R \to R$ by $h (x) = {\begin{cases} \max {f (x), g (x)} i f x \leq 0 \\ \min {f (x), g (x)} i f x > 0 \end{cases}$ Then number of points at which $h (x)$ is not differentiable is