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Q.

Let f(x) be a function such that f(x+y)=f(x)f(y)  for all  x,yN. If  f(1)=3 and k=1nf(k)=3279  then the value of n is

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a

6

b

8

c

7

d

9

answer is C.

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Detailed Solution

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f(x)=ax satisfies  f(x)+f(y)=f(x)f(y)

f(1)=a13=a        f(x)=ax=3x

k=1nf(x)=3279      3+32+33+......+3n=3279

3(3n1)2=3279     3n1=21863n=2187=37n=7

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