Let   $f\left(x\right)=\left({\left[k\right]}^2-5\left[k\right]+4\right)x^5-\left(6{\left\{k\right\}}^2-5\left\{k\right\}+1\right)x$  $-Tanx\left(\mathrm{sgn}\right(x\left)\right)$, be an even function for all  $x\in R$, where [.]denotes G.I.F and {.} denotes fractional part function. The sum of all possible values K is  $\lambda$ then $3\lambda =$