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Q.

Let f(x) = [x2]sinπx,xR, the number of points in the interval (0,3] at which the function is discontinuous is_____(where [.] denotes G.I.F)

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answer is 6.

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Detailed Solution

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f(x)=0<x<1= sinπx   1x<2                           =2sinπx  2x<3                           = 3sinπx  3x<2                           = 4sinπx  2x<5 etc.

The function is discontinuous at x=2,3,5,.......K where K is not a perfect square. Points of discontinuity (desired) = 2,3,5,6,7,8.

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