Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Let for the 9th term in the binomial expansion of (3 + 6x)n, in the increasing powers of 6x, to be the greatest for x=32, the least value of n is n0. If k is the ratio of the coefficient of x6 to the coefficient of x3, then k + n0 is equal to:

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 24.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

(3+6x)n=nC03n+nC13n1(6x)1+Tr+1nCr3nr(6x)r=nCr3nr6rxr=nCr3nr3r2r32r=nCr3n3r  for x=32

T9 is greatest of x=32

So, T9 > T10 and T9 > T8

(concept of numerically greatest term)

Here, T9T10>1 and T9T8>1

 nC83n38 nC93n39>1 and  nC83n38 nC73n37>1

and  nC8 nC7>13

and n78>13

293<n<11n=10=n0

So,  in (3+6x)n for n=n0=10

i.e.,  in (3+6x)10, here Tr+1=10Cr310r6rxr

T7=10C63466x6=21031026x6T4=10C33763x3=12031023x3

Ratio of coefficient of x6 and coefficient of x3 = k

k=21031026120.31023=74×23=14

So, k+n0=14+10=24

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Let for the 9th term in the binomial expansion of (3 + 6x)n, in the increasing powers of 6x, to be the greatest for x=32, the least value of n is n0. If k is the ratio of the coefficient of x6 to the coefficient of x3, then k + n0 is equal to: