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Q.

Let f(x) be a strictly increasing and differentiable function, then Ltx→0⁡fx2−f(x)f(x)−f(0)=

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a

2

b

1

c

-1/2

d

-1

answer is B.

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Detailed Solution

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Lttx→0fx2−f(x)f(x)−f(0)00 from  L.H Rule Ltx→0⁡f1x22x−f1(x)f1(x)−0=f1(0)2(0)−f1(0)f1(0)=0−f1(0)f1(0)=−1

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