Let fx=cospx , where p=a (integral part). If the period of f(x) is π then a∈

2πp=π⇒p=2⇒p=4∈[a]⇒a∈[4,5)

Let fx=cospx , where p=a (integral part). If the period of f(x) is π then a∈

2πp=π⇒p=2⇒p=4∈[a]⇒a∈[4,5)

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Let $f (x) = \cos \sqrt{p} x$ , where $p = [a]$ (integral part). If the period of $f (x)$ is $π$ then $a \in$

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(4, 5]

(4, 5)

[4, 5)

[4, 5]

answer is C.

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$\frac{2 π}{\sqrt{p}} = π \Rightarrow \sqrt{p} = 2 \Rightarrow p = 4 \in [a] \Rightarrow a \in [4, 5)$

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Let fx=cospx , where p=a (integral part). If the period of f(x) is π then a∈

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Let $f (x) = \cos \sqrt{p} x$ , where $p = [a]$ (integral part). If the period of $f (x)$ is $π$ then $a \in$