Q.

Let fx=sinx+ax+b, then fx=0 has :

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a

Only one real root which is positive, if a<–1 & b<0

b

Only one real root which is negative, if a>1 & b> 0

c

Only one real root which is positive, if a>1 & b<0

d

Only one real root which is negative, if a<–1 & b<0

answer is A, B, C.

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Detailed Solution

f1x=cosx+a and from the graphs

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