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Q.

Let f(x)=1+x2+x3  and x=y+1 , let g be a function such that ϕ(θ)=g(cos2θ) , then g(y)  and ϕ(θ)  are respectively

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a

None of these

b

y34y2+5y+3;8cos2θ+2cosθ+1

c

y3+4y2+5y+3;8cos2θ2cosθ+1

d

y3+4y2+5y+3;8cos6θ+4cos4θ+1

answer is A.

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Detailed Solution

g(y)=f(x)=x3+x2+1

          =(y+1)3+(y+1)2+1

          =y3+4y2+5y+3

ϕ(θ)=g(cos2θ)

          =cos32θ+4cos22θ+5cos2θ+3

          =(2cos2θ1)3+4(2cos2θ1)2+5(2cos2θ1)+3

          =8cos6θ+4cos4θ+1 .

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