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Let $f (x) = a x^{5} + b x^{3} + c,$ then when $f$ is odd,

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$c > 0$

$c < 0$

$c = 0$

$c \leq 0$

answer is C.

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Detailed Solution

$A f u n c t i o n i s o d d i f f (- x) = - f (x)$

$\Rightarrow - a x^{5} - b x^{3} + c = - a x^{5} - b x^{3} - c$

$\Rightarrow$ $c = 0$

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