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Let  f(x)=(ax+b)cosx+(cx+d)sinx and   f|(x)=xcosx be an identity in  x, then 

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a
a=0
b
b=1
c
c=1
d
d=0

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detailed solution

Correct option is A

f(x)=(ax+b)cosx+(cx+d)sinx

f|(x)=acosx(ax+b)sinx+c.sinx+(cx+d).cosx

=xcosx(c)+cosx(a+d)+sinx(b+c)+xsinx(a)

but  f|(x)=xcosx

c=1b+c=0b+1=0b=1

a=0a+d=0d=0

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