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Q.

Let g be the Inverse function of f and f1x=x101+x2, If  g2=a Then g12 is equal to

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a

5210

b

1+a10a2

c

1+a2a10

d

a101+a2

answer is B.

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Detailed Solution

∴gx is inverse of fx

⇒ gfx=x

⇒g1fxf1x=1

⇒g1fx=1+x2x10,as g2=a

Put x=a

⇒g1fa=1+a2a10

⇒fa=2

g12=1+a2a10

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