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Let $I_{0}$ be the intensity of light incident on a polarizer and $θ$ be the angle between the transmission directions of polarizer and analyzer
Value of $θ$ Intensity transmitted by analyser
a. $θ = 0^{0}$ p. $I_{0} / 2$
b. $θ = 45^{o}$ q. $I_{0} / 8$
c. $θ = 30^{o}$ r. $I_{0} / 4$
d. $θ = 60^{o}$ s. $3 I_{0} / 8$

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$a - p; b - r; c - s; d - q$

$a - r; b - p; c - q; d - s$

$a - s; b - p; c - q; d - r$

$a - r; b - s; c - q; d - p$

answer is A.

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Detailed Solution

$I^{1} = \frac{I_{0}}{2} \cos^{2} (θ)$

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