Let K be the sum of the coefficients of the odd powers of x in the expansion of ${\left(1+x\right)}^{99}$ . Let $a$ be the middle term in the expansion of ${\left(2+\frac{1}{\sqrt{2}}\right)}^{200}$  If  $\frac{{200}_{c_{99}}K}{a}=\frac{2^l.m}{n}$ ,  where m and n are odd numbers then  $l+n$ is equal to