Q.

Let LL' be the latus rectum through the focus of the  hyperbolax2a2y2b2=1 and, A' be the farther vertex. If ALL is equilateral, then the eccentricity of the hyperbola is

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a

(3+1)/2

b

(3+1)/3

c

3+1

d

3

answer is D.

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Detailed Solution

tan30=b2/aa+ae ⇒ 1+e3=e21 ⇒  e1=13 ⇒  e=3+13

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