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Q.

Let m and M be respectively the minimum and maximum values of |cos2x            1+sin2x          sin2x1+cos2 x         sin2x            sin2xcos2x                  sin2x       1+sin2x|  Then the ordered pair (m, M) is equal to 
 

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a

(−4,−1)

b

(1,3)

c

(−3,3)

d

(−3,−1)

answer is B.

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Detailed Solution

R2→R2→R1,R3→R3−R1

|cos2x     1+sin2x        sin2x1                    −1                     00                   −1                        1|=−2−sin2x=−3,−1

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