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Q.

Let n = 1!+ 4! + 7! + . . . +400!. Then ten's digit of n is

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a

2

b

7

c

1

d

6

answer is B.

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Detailed Solution

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1! = 1, 4! = 24,7!= 5040, 10! = 3628800. From 10! onwards the units place and tens place both have zeros. 

1! + 4! +7! = 1 + 24+ 5040 = 5065.

Ten's digit of n = ten's digit of 5065 = 6.

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Let n = 1!+ 4! + 7! + . . . +400!. Then ten's digit of n is