Q.

Let αn,   βn be the distinct roots of the equation x2+(n+1)x+n2=0. If n=220211(αn+1)(βn+1) can be expressed in the form ab, Where a and b are positive  integers relatively prime to each other, then the value of b-a is 

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Detailed Solution

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n=220211(αn+1)(βn+1)=n=220211n(n1)=n=220211(n1)1n=112021=20202021=ab

ba=1

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Let αn,   βn be the distinct roots of the equation x2+(n+1)x+n2=0. If ∑n=220211(αn+1)(βn+1) can be expressed in the form ab, Where a and b are positive  integers relatively prime to each other, then the value of b-a is