Let n(A-B) = 25 + x, n(B-A) = 2x and nA∩B=2x. If n(A) = 2(n(B)) then ‘x’ is

nA−B=25+x,nB−A=2xnA∩B=2x; nA=n(A−B)+nA∩B=25+x+2x=25+3xn(B)=nB−A+nA∩B=2x+2x=4xn(A)=2nB⇒25+3x=2(4x)⇒5x=25⇒x=5

Let n(A-B) = 25 + x, n(B-A) = 2x and nA∩B=2x. If n(A) = 2(n(B)) then ‘x’ is

nA−B=25+x,nB−A=2xnA∩B=2x; nA=n(A−B)+nA∩B=25+x+2x=25+3xn(B)=nB−A+nA∩B=2x+2x=4xn(A)=2nB⇒25+3x=2(4x)⇒5x=25⇒x=5

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Let n(A-B) = 25 + x, n(B-A) = 2x and $n (A \cap B) = 2 x$ . If n(A) = 2(n(B)) then ‘x’ is

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$n (A - B) = 25 + x, n (B - A) = 2 x$

$n (A \cap B) = 2 x; n (A) = n (A - B) + n (A \cap B)$

$= 25 + x + 2 x = 25 + 3 x$

$n (B) = n (B - A) + n (A \cap B) = 2 x + 2 x = 4 x$

$n (A) = 2 n (B) \Rightarrow 25 + 3 x = 2 (4 x)$

$\Rightarrow 5 x = 25 \Rightarrow x = 5$

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Let n(A-B) = 25 + x, n(B-A) = 2x and nA∩B=2x. If n(A) = 2(n(B)) then ‘x’ is

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Let n(A-B) = 25 + x, n(B-A) = 2x and $n (A \cap B) = 2 x$ . If n(A) = 2(n(B)) then ‘x’ is