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Q.

Let O be the centre of the circle  x2+y2=r2, where  r>52. Suppose PQ is a chord of this circle and  the equation of the line passing through P and Q is  2x+4y=5 . If the centre of the circumcircle of the triangle  OPQ lies on the line  x+2y=4 , then the value of r is

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answer is 2.

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Detailed Solution

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OA=52 OC=45CQ=OC=45 and CA=distance between the given parallel lines=325

 OQ=OA2+AQ2=OA2+CQ2CA2 54+165920=4 2=r

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