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Let P (2, -4) and Q (3, 1) be two given points. Let R (x, y) be a point such that ( x-2) (x-3) + (y-1) (y+4) = 0. If area of $Δ P Q R$ is $\frac{13}{2}$ , then the number of possible positions of R are

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answer is A.

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Detailed Solution

$Δ P Q R$ is the right angle triangle radius = altitude

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