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Q.

Let ‘P’ be a variable point on the ellipse  x2a2+y2b2=1  with foci S(ae,0)  and S/(ae,0). If A is the area of the triangle PSS1, then the maximum value of A (where e is eccentricity and  b2=a2(1e2))  is

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a

2 abe

b

ab2

c

abe

d

4abe

answer is C.

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Detailed Solution

Area A=|aebsinθ|,Amax=abe

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