Q.

Let P be the point of intersection of the three planes r.n1=0,r.n2=1 and r.n3=2 where n1,n2  and   n3 are 2j^+k^,  5i^12j^   and   3i^+4k^ respectively. Then the projection of  OP¯ on the Z – axis (O being origin) is

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a

92

b

112

c

72

d

132

answer is A.

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Detailed Solution

detailed_solution_thumbnail

 Let r=xi^+yi^+zk^

 So, 2y+z=0,5x12y=1,3x+4z=2

 Solving, z=72

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