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Let P be the pressure and V the volume of a gas such that PV = constant. If percentage error in P is k then percentage error in V is

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$\frac{1}{k}$

–k

answer is C.

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Detailed Solution

$\frac{dp}{p} \times 100 = k pv = e \Rightarrow v s p + \log v = \log c \Rightarrow \frac{1}{p} δp + \frac{1}{v} δv = 0 \frac{δp}{p} \times 100 = \frac{- δv}{v} \times 100 \Rightarrow \frac{δv}{v} \times 100 = - k$

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