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Q.

Let P = P={θ :sin θcos θ=2cos θ} and {Q=θ:sin θ+cos θ=2sin θ} be two sets, then

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a

PQ and Q~Pϕ

b

QP

c

PQ

d

P =Q

answer is D.

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Detailed Solution

 sin θ  cos θ= 2 cos θ

      sinθ = ( 2 +1 ) cos θ 

       cosθ = ( 2 -1 ) sin θ

        sin θ + cos θ= 2 sin θ

      P =Q

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