Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

Let p,q,r  be non-zero real numbers that are respectively the 10th,100th  and  1000th   terms of a harmonic progression. Consider the system of linear equations:
x+y+z=110x+100y+1000z=0 , (qr)x+(pr)y+(pq)z=0  

 Column-I Column-II
(I)If  qr=10,  then the system of linear equations has(P)x=0,y=109,z=19  as a solution
(II)If pr100,  then the system of linear equations has(Q)x=109,y=19,z=0  as a solution
(III)If pq10,  then the system of linear equations has(R)infinitely many solutions
(IV)If  pq=10,  then the system of linear equations has(S)no solution
  (T)at least one solution

The correct option is:

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

(I)-(T); (II)-(S); (III)-(P); (IV)-(T)

b

(I)-(Q); (II)-(R); (III)-(P); (IV)-(R) 

c

(I)-(T); (II)-(R); (III)-(S); (IV)-(T) 

d

(I)-(Q); (II)-(S); (III)-(S); (IV)-(R)

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

(I) qr=10D=Dx=Dy=Dz=0 
So, there will be infinitely many solutions and they will be of the type (x,y,z)=(109+10λ,1911λ,λ)  which gives (I)-(Q),(R),(T)
(II)  pr100Dy0
So, no solution which gives (II)-(S)
(III)  pq10Dz0
So, no solution which gives (III)-(S)
(IV)  pq=10Dx=Dy=Dz=D=0
So, infinitely many solutions which give (IV)-(Q),(R),(T)

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Let p,q,r  be non-zero real numbers that are respectively the 10th,100th  and  1000th   terms of a harmonic progression. Consider the system of linear equations:x+y+z=1, 10x+100y+1000z=0 , (qr)x+(pr)y+(pq)z=0   Column-I Column-II(I)If  qr=10,  then the system of linear equations has(P)x=0,y=109,z=−19  as a solution(II)If pr≠100,  then the system of linear equations has(Q)x=109,y=−19,z=0  as a solution(III)If pq≠10,  then the system of linear equations has(R)infinitely many solutions(IV)If  pq=10,  then the system of linear equations has(S)no solution  (T)at least one solutionThe correct option is: