$\text{ Let }P=\left\{(x,y)\mid x^2+y^2=1,x,y\in R\right\}\text{ . Then, }P\text{ is }$

$$\begin{gathered} P=\left\{(x,y)\mid x^2+y^2=1,x,y\in R\right\} \\ Obviously P is not reflexive, because (1,1) is not an element of R \\ If (x,y) is an element of P then (y,x) also an element of P \\ So, P is symmetric \\ (0,1), (1,0) are elements of P but (0,0) is not an element of P \\ So that the relation P is not transitive \\ Hence, the relation P is not reflexive, symmetric, not Transitive. \\ Therefore, the 2nd option is correct \end{gathered}$$